{"id":91,"date":"2023-02-14T14:35:00","date_gmt":"2023-02-14T14:35:00","guid":{"rendered":""},"modified":"2023-10-10T05:34:16","modified_gmt":"2023-10-10T05:34:16","slug":"1-%e0%a4%b8%e0%a4%82%e0%a4%ac%e0%a4%82%e0%a4%a7-%e0%a4%8f%e0%a4%b5%e0%a4%82-%e0%a4%ab%e0%a4%b2%e0%a4%a8","status":"publish","type":"post","link":"https:\/\/class12.studyguruji.in\/?p=91","title":{"rendered":"1. \u0938\u0902\u092c\u0902\u0927 \u090f\u0935\u0902 \u092b\u0932\u0928"},"content":{"rendered":"

1.\u00a0\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0915\u093f\u0938\u0915\u093e \u092a\u094d\u0930\u0924\u093f\u0932\u094b\u092e \u092b\u0932\u0928 \u0939\u094b\u0924\u093e \u0939\u0948\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A)\u00a0\u090f\u0915\u0948\u0915 \u0905\u0902\u0924\u0903 \u0915\u094d\u0937\u0947\u092a\u0940<\/span><\/span><\/p>\n

(B)\u00a0\u090f\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

(C)\u00a0\u0905\u0928\u0947\u0915\u0948\u0915 \u0905\u0902\u0924\u0903 \u0915\u094d\u0937\u0947\u092a\u0940<\/span><\/span><\/p>\n

(D)\u00a0\u0905\u0928\u0947\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

2.\u00a0\u0938\u092e\u0941\u091a\u094d\u091a\u092f\u00a0<\/span>A = {1.2.3);\u00a0\u0915\u0947 \u0915\u0941\u0932 \u0915\u093f\u0924\u0928\u0947 \u092d\u093f\u0928\u094d\u0928 \u0938\u0902\u092c\u0902\u0927 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0915\u093f\u090f \u091c\u093e \u0938\u0915\u0924\u0947 \u0939\u0948\u0902\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A) 2\u2079\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(B) 2\u00b3<\/span><\/p>\n

(C) 9<\/span><\/p>\n

(D) 2\u2076<\/span><\/p>\n

\u00a0<\/span><\/p>\n

3.\u00a0\u092f\u0926\u093f\u00a0<\/span>A = { 1, 2, 3 },\u00a0\u0924\u094b\u00a0<\/span>A\u00a0\u0938\u0947\u00a0<\/span>A\u00a0\u092a\u0930 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0938\u092d\u0940 \u090f\u0915\u0948\u0915 \u092b\u0932\u0928\u094b \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u0939\u0948\u0964<\/span><\/span><\/b><\/span><\/p>\n

(A) 2<\/span><\/p>\n

(B) 3<\/span><\/p>\n

(C) 4<\/span><\/p>\n

(D) 6\u00a0\u2713<\/span><\/b><\/span><\/p>\n

\u00a0<\/span><\/p>\n

4.\u00a0\u092f\u0926\u093f\u00a0<\/span>A = { 1, 2, 3 }, B = { 2, 5, 10, 17 }\u00a0\u0914\u0930\u00a0<\/span>f(x)=x\u00b2+1\u00a0\u0924\u094b \u092b\u0932\u0928\u00a0<\/span>f: A\u00a0<\/span><\/b>\u2192<\/span><\/b>\u00a0B\u00a0\u0915\u0948\u0938\u093e \u092b\u0932\u0928 \u0939\u094b\u0917\u093e\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A)\u00a0\u090f\u0915\u0947\u0915 \u0905\u0902\u0924 \u0915\u094d\u0937\u0947\u092a\u0940\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

(B)\u00a0\u090f\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915<\/span><\/span><\/p>\n

(C)\u00a0\u0905\u0928\u0947\u0915 \u0905\u0902\u0924 \u0915\u094d\u0937\u0947\u092a\u0940<\/span><\/span><\/p>\n

(D)\u00a0\u0905\u0928\u0947\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

5.\u00a0\u092f\u0926\u093f\u00a0<\/span>A = (5,6);\u00a0\u0907\u0938 \u0938\u092e\u0941\u091a\u094d\u091a\u092f \u092a\u0930 \u0915\u093f\u0924\u0928\u0940 \u0926\u094d\u0935\u093f\u091a\u0930 \u0938\u0902\u0915\u094d\u0930\u093f\u092f\u093e\u090f\u0901 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0939\u094b \u0938\u0915\u0924\u0940 \u0939\u0948\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A) 8<\/span><\/p>\n

(B) 10<\/span><\/p>\n

(C) 16\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(D) 20<\/span><\/p>\n

\u00a0<\/span><\/p>\n

6.\u00a0\u092f\u0926\u093f\u00a0<\/span>A={1, 2, 3}, B= {6, 7, 8}\u00a0\u0924\u0925\u093e\u00a0<\/span>f: A<\/span><\/b>\u2192<\/span><\/b>B :\u00a0\u090f\u0915 \u092b\u0932\u0928 \u0939\u0948 \u0907\u0938 \u092a\u094d\u0930\u0915\u093e\u0930 \u0915\u093f\u00a0<\/span>f(x)=x+5,\u00a0\u0924\u094b\u00a0<\/span>f\u00a0\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0938\u0947 \u0915\u093f\u0938 \u092a\u094d\u0930\u0915\u093e\u0930 \u0915\u093e \u092b\u0932\u0928 \u0939\u0948\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A)\u00a0\u0905\u0902\u0924 \u0915\u094d\u0937\u0947\u092a\u0940<\/span><\/span><\/p>\n

(B)\u00a0\u090f\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

(C)\u00a0\u0905\u0928\u0947\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915<\/span><\/span><\/p>\n

(D)\u00a0\u0905\u091a\u0930 \u092b\u0932\u0928<\/span><\/span><\/p>\n

\u00a0<\/span><\/span><\/b><\/p>\n

7.\u00a0\u092f\u0926\u093f :\u00a0<\/span>f A\u00a0<\/span><\/b>\u2192<\/span><\/b>\u00a0B\u00a0\u090f\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915 \u0939\u094b<\/span>,\u00a0\u0924\u094b \u2013<\/span><\/span><\/b><\/span><\/p>\n

(A) n(A) > (B)<\/span><\/p>\n

(B) n (A) <n (B)<\/span><\/p>\n

(C) n(A) = n(B)\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(D)\u00a0\u0907\u0928\u092e\u0947\u0902 \u0938\u0947 \u0915\u094b\u0908 \u0928\u0939\u0940\u0902<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

\u00a0<\/span><\/span><\/b><\/p>\n

8.\u00a0\u092f\u0926\u093f\u00a0<\/span>A = {a, b, c}, B = {1, 2, 3}\u00a0\u0914\u0930\u00a0<\/span>f = { (a, 1), (b, 2), (c, 2)}\u00a0\u0924\u094b\u00a0<\/span>f\u00a0\u0915\u0948\u0938\u093e \u092b\u0932\u0928 \u0939\u0948:<\/span><\/span><\/b><\/span><\/p>\n

(A)\u00a0\u090f\u0915\u0948\u0915 \u0905\u0902\u0924\u0903\u0915\u094d\u0937\u0947\u092a\u0940<\/span><\/span><\/p>\n

(B)\u00a0\u0905\u0928\u0947\u0915\u0948\u0915 \u0905\u0902\u0924\u0903\u0915\u094d\u0937\u0947\u092a\u0940\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

(C)\u00a0\u0905\u0928\u0947\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915<\/span><\/span><\/p>\n

(D)\u00a0\u090f\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

9.\u00a0\u0915\u093f\u0938\u0940 \u0938\u092e\u0924\u0932 \u0915\u0940 \u0938\u092d\u0940 \u0938\u0930\u0932 \u0930\u0947\u0916\u093e\u0913\u0902 \u0915\u0947 \u0938\u092e\u0941\u091a\u094d\u091a\u092f \u092e\u0947\u0902 \u2018<\/span>R\u2019\u00a0\u0932\u092e\u094d\u092c \u0939\u094b\u0928\u0947 \u0915\u093e \u0938\u0902\u092c\u0902\u0927 \u0939\u0948\u201d<\/span>,\u00a0\u0924\u094b \u0938\u0902\u092c\u0902\u0927\u00a0<\/span>R :<\/span><\/b><\/span><\/p>\n

(A)\u00a0\u0938\u094d\u0935\u0924\u0941\u0932\u094d\u092f \u0914\u0930 \u0938\u0902\u0915\u094d\u0930\u093e\u092e\u0915 \u0939\u0948<\/span><\/span><\/p>\n

(B)\u00a0\u0938\u092e\u092e\u093f\u0924 \u0914\u0930 \u0938\u0902\u0915\u094d\u0930\u093e\u092e\u0915 \u0939\u0948<\/span><\/span><\/p>\n

(C)\u00a0\u0938\u092e\u092e\u093f\u0924 \u0939\u0948\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

(D)\u00a0\u0907\u0928\u092e\u0947\u0902 \u0938\u0947 \u0915\u094b\u0908 \u0928\u0939\u0940<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

10.\u00a0\u092f\u0926\u093f \u0938\u0902\u0915\u094d\u0930\u093f\u092f\u093e *<\/span>, a * b = 2a + b\u00a0\u0938\u0947 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0939\u094b<\/span>,\u00a0\u0924\u094b (<\/span>23)<\/i>4\u00a0\u0939\u0948:<\/span><\/span><\/b><\/span><\/p>\n

(A) 18\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(B) 17<\/span><\/p>\n

(C) 19<\/span><\/p>\n

(D) 21<\/span><\/p>\n

\u00a0<\/span><\/p>\n

11.\u00a0\u092f\u0926\u093f * \u0938\u0902\u0915\u094d\u0930\u093f\u092f\u093e\u00a0<\/span>a * b = 3a + 4b \u2013 2\u00a0\u0938\u0947 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0939\u094b \u0924\u094b\u00a0<\/span>4 * 5\u00a0\u0939\u0948 :<\/span><\/span><\/b><\/span><\/p>\n

(A) 30\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(B) 20<\/span><\/p>\n

(C) 10<\/span><\/p>\n

(D) 15<\/span><\/p>\n

\u00a0<\/span><\/p>\n

12.\u00a0\u092e\u093e\u0928 \u0932\u0940\u091c\u093f\u090f \u0915\u093f \u0938\u092e\u0941\u091a\u094d\u091a\u092f\u00a0<\/span>N\u00a0\u092e\u0947\u0902\u00a0<\/span>R= { (a, b) : a= b \u2013 2, b > 6}\u00a0\u0926\u094d\u0935\u093e\u0930\u093e \u092a\u094d\u0930\u0926\u0924\u094d\u0924 \u0938\u0902\u092c\u0902\u0927\u00a0<\/span>R\u00a0\u0939\u0948\u0964 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0938\u0947 \u0938\u0939\u0940 \u0909\u0924\u094d\u0924\u0930 \u0939\u0948 :<\/span><\/span><\/b><\/span><\/p>\n

(A) (6,8) \u22f3 R\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(B) (2, 4) \u22f3 R<\/span><\/p>\n

(C) (3,8) \u22f3 R<\/span><\/p>\n

(D) (8, 7) \u22f3 R<\/span><\/p>\n

\u00a0<\/span><\/p>\n

13.\u00a0\u092f\u0926\u093f\u00a0<\/span>f(x)=(x\u00b2-1)\u00a0\u0914\u0930\u00a0<\/span>g(x)=(2x+3)\u00a0\u0924\u094b (<\/span>g of) (x) = ?<\/span><\/b><\/span><\/p>\n

(A) (2x\u00b2 + 1)\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(B) (2x\u00b2 + 3)<\/span><\/p>\n

(C) (3x\u00b2 + 2)<\/span><\/p>\n

(D)\u00a0\u0907\u0928\u092e\u0947\u0902 \u0938\u0947 \u0915\u094b\u0908 \u0928\u0939\u0940\u0902<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

14.\u00a0\u092f\u0926\u093f\u00a0<\/span>f: A\u00a0<\/span><\/b>\u2192<\/span><\/b>\u00a0B\u00a0\u0924\u0925\u093e\u00a0<\/span>g : B\u00a0<\/span><\/b>\u2192<\/span><\/b>\u00a0C\u00a0\u090f\u0915\u0948\u0915 \u0939\u0948\u0902<\/span>,\u00a0\u0924\u094b\u00a0<\/span>gof: A\u00a0<\/span><\/b>\u2192<\/span><\/b>\u00a0C<\/span><\/b><\/span><\/p>\n

(A)\u00a0\u090f\u0915\u0948\u0915 \u0939\u0948\u0902\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

(B)\u00a0\u0905\u0928\u0947\u0915\u0948\u0915 \u0939\u0948<\/span><\/span><\/p>\n

(C)\u00a0\u0926\u094b\u0928\u094b\u0902<\/span>\u00a0\u0939\u0948<\/span><\/span><\/p>\n

(D)\u00a0\u0907\u0928\u092e\u0947\u0902 \u0938\u0947 \u0915\u094b\u0908 \u0928\u0939\u0940<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

15.\u00a0\u092f\u0926\u093f * \u0938\u0902\u0915\u094d\u0930\u093f\u092f\u093e \u0915\u0940 \u092a\u0930\u093f\u092d\u093e\u0937\u093e \u0939\u0948 \u0915\u093f\u00a0<\/span>ab=a\u00b2d\u00b2,\u00a0\u0924\u094b (<\/span>1<\/i>2)*6\u00a0\u0939\u0948:<\/span><\/span><\/b><\/span><\/p>\n

(A) 12<\/span><\/p>\n

(B) 28<\/span><\/p>\n

(C) 61\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(D)\u00a0\u0907\u0928\u092e\u0947\u0902 \u0938\u0947 \u0915\u094b\u0908 \u0928\u0939\u0940\u0902<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

16. R= {(1, 3), (4, 2), (2, 4), (2, 3), (3, 1)}\u00a0\u0938\u092e\u0941\u091a\u094d\u091a\u092f\u00a0<\/span>A= (1.2, 3, 4)\u00a0\u092a\u0930 \u0915\u0948\u0938\u093e \u0938\u0902\u092c\u0902\u0927 \u0939\u0948\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A)\u00a0\u0938\u094d\u0935\u0924\u0941\u0932\u094d\u092f<\/span><\/span><\/p>\n

(B)\u00a0\u0938\u0902\u0915\u093e\u092e\u0915<\/span><\/span><\/p>\n

(C)\u00a0\u0938\u092e\u092e\u093f\u0924<\/span><\/span><\/p>\n

(D)\u00a0\u0907\u0928\u092e\u0947\u0902 \u0938\u0947 \u0915\u094b\u0908 \u0928\u0939\u0940\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

\u00a0<\/span><\/p>\n

17.\u00a0\u092f\u0926\u093f :\u00a0<\/span>$\\displaystyle f:R\\to R$\u00a0\u091c\u0939\u093e\u0901\u00a0<\/span>$\\displaystyle f(x)=5x+4$\u00a0\u0939\u094b<\/span>,\u00a0\u0924\u094b\u00a0<\/span>$\\displaystyle {{f}^{{-1}}}(x)$\u00a0\u0928\u093f\u092e\u094d\u0928 \u092e\u0947\u0902 \u0938\u0947 \u0915\u094c\u0928 \u0939\u094b\u0917\u093e\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A) $\\displaystyle \\frac{{x-5}}{4}$<\/span><\/p>\n

(B) $\\displaystyle \\frac{{x-y}}{5}$<\/span><\/p>\n

(C) $\\displaystyle \\frac{{x-4}}{5}$\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(D) $\\displaystyle \\frac{x}{5}-5$<\/span><\/p>\n

\u00a0<\/span><\/p>\n

18.\u00a0\u092f\u0926\u093f\u00a0<\/span>n (A)=3\u00a0\u0924\u0925\u093e\u00a0<\/span>n (B)=2\u00a0\u0924\u094b (<\/span>A x B)=\u2026.<\/span><\/b><\/span><\/p>\n

(A) 6\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(B) 4<\/span><\/p>\n

(C) 2<\/span><\/p>\n

(D) 0<\/span><\/p>\n

\u00a0<\/span><\/p>\n

19. x*y=1+12x+xy,\u00a0<\/span><\/b>\u2200<\/span><\/b>\u00a0xy \u20ac Q\u00a0\u0926\u094d\u0935\u093e\u0930\u093e \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924\u00a0<\/span>Q\u00a0\u092a\u0930 \u090f\u0915 \u0926\u094d\u0935\u093f\u0906\u0927\u093e\u0930\u0940 \u0938\u0902\u0915\u094d\u0930\u093f\u092f\u093e \u0915\u0940 \u0935\u093f\u0935\u0947\u091a\u0928\u093e \u0915\u0930\u0947\u0902\u0964 \u0924\u092c\u00a0<\/span>2 * 3\u00a0\u0915\u093e \u092e\u093e\u0928 \u0939\u094b\u0917\u093e :<\/span><\/span><\/b><\/span><\/p>\n

(A) 31\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(B) 41<\/span><\/p>\n

(C) 43<\/span><\/p>\n

(D) 51<\/span><\/p>\n

\u00a0<\/span><\/p>\n

20. A B\u00a0\u090f\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915 \u092b\u0932\u0928 \u0939\u094b\u0917\u093e<\/span>,\u00a0\u092f\u0926\u093f<\/span><\/span><\/b><\/span><\/p>\n

(A) f(A) \u2282 B<\/span><\/p>\n

(B) f(A) = B\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(C) B \u2282 f(A)<\/span><\/p>\n

(D) f(B) \u2282 A<\/span><\/p>\n

\u00a0<\/span><\/p>\n

21.\u00a0\u092b\u0932\u0928<\/span>\u00a0$\\displaystyle f(x)=\\sqrt{{(x-1)(3-x)}}$\u00a0\u0915\u093e \u092a\u0930\u093e\u0938 \u0939\u0948\u0964<\/span><\/span><\/b><\/span><\/p>\n

(A) [1, 3]\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(B) (0, 1)<\/span><\/p>\n

(C) (-2, 2)<\/span><\/p>\n

(D)\u00a0\u0907\u0928\u092e\u0947\u0902 \u0938\u0947 \u0915\u094b\u0908 \u0928\u0939\u0940<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

22.\u00a0\u092f\u0926\u093f\u00a0<\/span>$\\displaystyle f:R\\to R$\u00a0\u0907\u0938 \u0924\u0930\u0939 \u0938\u0947 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0939\u094b \u0915\u093f\u00a0<\/span>$\\displaystyle f(x)=2x+3$\u00a0\u0924\u094b\u00a0<\/span>$\\displaystyle {{f}^{{-1}}}(x)=$<\/span><\/b><\/span><\/p>\n

(A) $\\displaystyle 2x-1$<\/span><\/p>\n

(B) $\\displaystyle \\frac{{x-3}}{2}$\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(C) $\\displaystyle \\frac{{x+3}}{2}$<\/span><\/p>\n

(D)\u00a0\u0907\u0928\u092e\u0947\u0902 \u0938\u0947 \u0915\u094b\u0908 \u0928\u0939\u0940\u0902<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

23.\u00a0\u092f\u0926\u093f\u00a0<\/span>$\\displaystyle f(x)+2f(1-x)={{x}^{2}}+2\\forall x\\in R$\u00a0\u0924\u094b\u00a0<\/span>$\\displaystyle f(x)=$<\/span><\/b><\/span><\/p>\n

(A) $\\displaystyle {{x}^{2}}-3$<\/span><\/p>\n

(B) 1<\/span><\/p>\n

(C) $\\displaystyle \\frac{1}{2}{{(x-2)}^{2}}$\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(D)\u00a0\u0907\u0928\u092e\u0947\u0902 \u0938\u0947 \u0915\u094b\u0908 \u0928\u0939\u0940<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

24. sin\u00b2<\/span><\/b>\u03b8<\/span><\/b>\u00a0\u0915\u093e \u0906\u092a \u0915\u093e\u0932 \u0939\u0948\u0964<\/span><\/span><\/b><\/span><\/p>\n

(A) \u03c0\u00b2<\/span><\/p>\n

(B) \u03c0\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(C) 2\u03c0<\/span><\/p>\n

(D) $\\displaystyle \\frac{\\pi }{2}$<\/span><\/p>\n

\u00a0<\/span><\/p>\n

25. $\\displaystyle {{\\sin }^{{-1}}}[{{\\log }_{3}}(\\frac{x}{3})]$\u00a0\u0915\u093e \u092a\u094d\u0930\u093e\u0902\u0924 \u0939\u0948\u0964<\/span><\/span><\/b><\/span><\/p>\n

(A) [1,9]\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(B) [-1,9]<\/span><\/p>\n

(C) [-9,1]<\/span><\/p>\n

(D) [-9,-1]<\/span><\/p>\n

\u00a0<\/span><\/p>\n

26.\u00a0\u092b\u0932\u0928\u00a0<\/span>$\\displaystyle f(x)={{\\sin }^{4}}x+{{\\cos }^{4}}x$\u00a0\u0915\u093e \u0906\u0935\u0930\u094d\u0924\u0915\u093e\u0932 \u0939\u0948\u0964<\/span><\/span><\/b><\/span><\/p>\n

(A) \u03c0<\/span><\/p>\n

(B) $\\displaystyle \\frac{\\pi }{2}$\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(C) $\\displaystyle 2\\pi $<\/span><\/p>\n

(D)\u00a0\u0915\u094b\u0908 \u0928\u0939\u0940\u0902<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

27.\u00a0\u092b\u0932\u0928\u00a0<\/span>$\\displaystyle f(x)=\\log (x+\\sqrt{{{{x}^{2}}+1}})$\u00a0\u0915\u093e \u0905\u0938\u094d\u0924\u093f\u0924\u094d\u0935 \u0939\u0948-<\/span><\/span><\/b><\/span><\/p>\n

(A)\u00a0\u0938\u092e \u092b\u0932\u0928<\/span><\/span><\/p>\n

(B)\u00a0\u0935\u093f\u0937\u092e\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

(C)\u00a0\u0906\u0935\u0930\u094d\u0924\u0940 \u092b\u0932\u0928<\/span><\/span><\/p>\n

(D)\u00a0\u0928 \u0924\u094b \u0938\u092e \u0914\u0930 \u0928 \u0939\u0940 \u0935\u093f\u0937\u092e<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

28.\u00a0\u092e\u093e\u0928\u093e\u00a0<\/span>A = {1, 2, 3}\u00a0\u0924\u0925\u093e\u00a0<\/span>R = {(1, 2), (1, 1).(2, 2).(2, 1)}\u00a0\u0914\u0930 \u092e\u093e\u0928\u093e\u00a0<\/span>R, A\u00a0\u092a\u0930 \u090f\u0915 \u0938\u0902\u092c\u0902\u0927 \u0939\u094b \u0924\u094b\u00a0<\/span>R\u00a0\u0939\u0948\u0902<\/span><\/span><\/b><\/span><\/p>\n

(A)\u00a0\u0938\u0902\u0915\u094d\u0930\u093e\u092e\u0915\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

(B)\u00a0\u0938\u094d\u0935\u0924\u0941\u0932\u094d\u092f<\/span><\/span><\/p>\n

(C)\u00a0\u0938\u092e\u092e\u093f\u0924<\/span><\/span><\/p>\n

(D)\u00a0\u0915\u094b\u0908<\/span>\u00a0\u0928\u0939\u0940<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

29.\u00a0\u092f\u0926\u093f\u00a0<\/span>$\\displaystyle (If)A={1,2,3},b={5,6,7}$\u00a0\u0924\u0925\u093e\u00a0<\/span>$\\displaystyle f:A\\to B$\u00a0\u090f\u0915 \u092b\u0932\u0928 \u0939\u0948 \u091c\u0948\u0938\u093e \u0915\u093f\u00a0<\/span>$\\displaystyle f(x)=x+4$\u00a0\u0924\u094b\u00a0<\/span>$\\displaystyle f$\u00a0\u0915\u093f\u0938 \u092a\u094d\u0930\u0915\u093e\u0930 \u0915\u093e \u092b\u0932\u0928 \u0939\u0948\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A)\u00a0\u0905\u0928\u0947\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915<\/span><\/span><\/p>\n

(B)\u00a0\u0905\u0935\u0930 \u092b\u0932\u0928<\/span><\/span><\/p>\n

(C)\u00a0\u090f\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

(D)\u00a0\u0905\u0902\u0924:\u0936\u094d\u0930\u0947\u0923\u0940<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

30.\u00a0\u092e\u093e\u0928\u093e \u092b\u0932\u0928\u00a0<\/span>$\\displaystyle f:R\\to R,f(x)=2{{x}^{3}}-1$\u00a0\u092a\u094d\u0930\u0915\u093e\u0930 \u0938\u0947 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0939\u0948<\/span>,\u00a0\u0924\u092c\u00a0<\/span>$\\displaystyle {{f}^{{-1}}}$\u00a0\u0939\u0948\u0964<\/span><\/span><\/b><\/span><\/p>\n

(A) $\\displaystyle 2{{x}^{3}}+1$<\/span><\/p>\n

(B) $\\displaystyle {{(2x)}^{3}}+1$<\/span><\/p>\n

(C) $\\displaystyle {{(1-2x)}^{3}}$<\/span><\/p>\n

(D) $\\displaystyle {{(\\frac{{1+x}}{2})}^{{\\frac{1}{3}}}}$\u00a0\u2713<\/span><\/b><\/span><\/p>\n

\u00a0<\/span><\/p>\n

31.\u00a0\u090f\u0915 \u0905\u0930\u093f\u0915\u094d\u0924 \u0938\u092e\u0941\u091a\u094d\u091a\u092f\u00a0<\/span>A\u00a0\u092a\u0930 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u090f\u0915 \u0938\u0902\u092c\u0902\u0927 \u091c\u094b \u0905\u0935\u092f\u0935\u094b\u0902 \u0915\u094b \u0930\u0916\u0924\u093e \u0939\u0948<\/span><\/span><\/b><\/span><\/p>\n

(A) n\u00a0\u0938\u0902\u092c\u0902\u0927<\/span><\/span><\/p>\n

(B) 2\u00a0\u0938\u0902\u092c\u0902\u0927<\/span><\/span><\/p>\n

(C) n\u00b2\u00a0\u092e\u0947\u0902 \u0938\u0902\u092c\u0902\u0927<\/span><\/span><\/p>\n

(D) $\\displaystyle {{2}^{{{{n}^{2}}}}}$\u00a0\u0938\u0902\u092c\u0902\u0927\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

\u00a0<\/span><\/p>\n

32. $\\displaystyle f:A\\to B$\u00a0\u0906\u091a\u094d\u091b\u093e\u0926\u0915 \u092b\u0932\u0928 \u0939\u094b\u0917\u093e<\/span>,\u00a0\u092f\u0926\u093f:<\/span><\/span><\/b><\/span><\/p>\n

(A) $\\displaystyle f(A)\\subset B$<\/span><\/p>\n

(B) $\\displaystyle f(A)=B$\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(C) $\\displaystyle f(A)\\supset B$<\/span><\/p>\n

(D) $\\displaystyle f(A)\\ne B$<\/span><\/p>\n

\u00a0<\/span><\/p>\n

33. $\\displaystyle f:A\\to B$\u00a0\u0905\u0902\u0924\u0903 \u0915\u094d\u0937\u0947\u092a\u0940 \u0939\u094b\u0917\u093e<\/span>,\u00a0\u092f\u0926\u093f :<\/span><\/span><\/b><\/span><\/p>\n

(A) $\\displaystyle f(A)\\subset B$\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(B) $\\displaystyle f(A)=B$<\/span><\/p>\n

(C) $\\displaystyle f(B)\\supset A$<\/span><\/p>\n

(D) $\\displaystyle f(B)\\ne A$<\/span><\/p>\n

\u00a0<\/span><\/p>\n

34.\u00a0\u092f\u0926\u093f\u00a0<\/span>$\\displaystyle f:R\\to R$\u00a0\u091c\u0939\u093e\u0901\u00a0<\/span>$\\displaystyle f(x)={{x}^{2}}$\u00a0\u0924\u094b\u00a0<\/span>$\\displaystyle f$\u00a0\u0915\u0948\u0938\u093e \u092b\u0932\u0928 \u0939\u0948\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A) injective, not surjective<\/span><\/p>\n

(B) surjective, not injective<\/span><\/p>\n

(C) bijective<\/span><\/p>\n

(D) neither injective nor surjective\u00a0\u2713<\/span><\/b><\/span><\/p>\n

\u00a0<\/span><\/p>\n

35.\u00a0\u092f\u0926\u093f\u00a0<\/span>$\\displaystyle f:R\\to R$\u00a0\u091c\u0939\u093e\u0901\u00a0<\/span>$\\displaystyle f(x)=3x-4$\u00a0\u0924\u094b\u00a0<\/span>$\\displaystyle {{f}^{1}},R\\to R$\u00a0\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0915\u094c\u0928 \u0939\u094b\u0917\u093e\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A) $\\displaystyle \\frac{1}{2}(x+4)$\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(B) $\\displaystyle \\frac{1}{2}(x-4)$<\/span><\/p>\n

(C) $\\displaystyle 3x-4$<\/span><\/p>\n

(D) underfine<\/span><\/p>\n

\u00a0<\/span><\/p>\n

36.\u00a0\u092f\u0926\u093f\u00a0<\/span>$\\displaystyle f:R\\to R$\u00a0\u090f\u0915 \u092b\u0932\u0928 \u0939\u094b<\/span>,\u00a0\u0924\u094b\u00a0<\/span>$\\displaystyle {{f}^{{-1}}},R\\to R$\u00a0\u092a\u094d\u0930\u093e\u092a\u094d\u0924 \u0939\u094b\u0917\u093e\u00a0<\/span>?\u00a0\u092f\u0926\u093f\u00a0<\/span>$\\displaystyle f$\u00a0\u0939\u094b\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A)\u00a0\u090f\u0915\u0948\u0915 \u0905\u0902\u0924\u0903\u0936\u094d\u0930\u0947\u0937\u0940<\/span><\/span><\/p>\n

(B)\u00a0\u0906\u091a\u094d\u091b\u093e\u0926\u0915<\/span><\/span><\/p>\n

(C)\u00a0\u090f\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

(D)\u00a0\u0905\u0928\u0947\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

37.\u00a0\u092e\u093e\u0928\u093e \u0915\u093f\u00a0<\/span>A = {1, 2, 3}\u00a0\u0924\u094b (<\/span>1, 2)\u00a0\u0914\u0930 (<\/span>1, 3)\u00a0\u0915\u094b \u0936\u093e\u092e\u093f\u0932 \u0915\u0930\u0924\u0947 \u0939\u0941\u090f \u0915\u093f\u0924\u0928\u0947 \u0938\u0902\u092c\u0902\u0927\u00a0<\/span>A\u00a0\u092a\u0930 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0939\u094b \u0938\u0915\u0924\u0947 \u0939\u0948 \u091c\u094b \u0938\u094d\u0935\u0924\u0941\u0932\u094d\u092f \u0938\u092e\u092e\u093f\u0924 \u0939\u0948 \u0915\u093f\u0902\u0924\u0941 \u0938\u0902\u0915\u094d\u0930\u093e\u092e\u0915 \u0928\u0939\u0940\u0902\u00a0<\/span>?.<\/span><\/b><\/span><\/p>\n

(A) 4<\/span><\/p>\n

(B) 3<\/span><\/p>\n

(C) 2<\/span><\/p>\n

(D) 1\u00a0\u2713<\/span><\/b><\/span><\/p>\n

\u00a0<\/span><\/p>\n

38.\u00a0\u092f\u0926\u093f\u00a0<\/span>$\\displaystyle f:R\\to R$\u00a0\u091c\u0939\u093e\u0901\u00a0<\/span>$\\displaystyle f(x)={{x}^{2}}-3x+2$\u00a0\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0915\u094c\u0928 \u0939\u094b\u0917\u093e\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A) 1<\/span><\/p>\n

(B) 0<\/span><\/p>\n

(C) 2\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(D) -1<\/span><\/p>\n

\u00a0<\/span><\/p>\n

39.\u00a0\u092e\u093e\u0928\u093e \u0915\u093f\u00a0<\/span>A= {1.2}\u00a0\u0907\u0938 \u0938\u092e\u0941\u091a\u094d\u091a\u092f \u092a\u0930 \u0915\u093f\u0924\u0928\u0947 \u0926\u094d\u0935\u093f\u0928\u0930 \u0938\u0902\u0915\u094d\u0930\u093f\u092f\u093e\u090f\u0901 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0939\u094b \u0938\u0915\u0924\u0947 \u0939\u0948\u00a0<\/span>?<\/span><\/b>
\n\u092f\u093e<\/span>,
\n\u0938\u092e\u0941\u091a\u094d\u091a\u092f\u00a0<\/span>{a, b}\u00a0\u092e\u0947\u0902 \u0926\u094d\u0935\u093f\u0906\u0927\u093e\u0930\u0940 \u0938\u0902\u0915\u094d\u0930\u093f\u092f\u093e\u0913\u0902 \u0915\u0940 \u0938\u0902\u0916\u094d\u092f\u093e \u0939\u0948 :<\/span><\/span><\/b><\/span><\/p>\n

(A) 8<\/span><\/p>\n

(B) 10<\/span><\/p>\n

(C) 16\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(D) 20<\/span><\/p>\n

\u00a0<\/span><\/p>\n

40. $\\displaystyle aob={{a}^{3}}+{{b}^{2}}$\u00a0\u092a\u094d\u0930\u0915\u093e\u0930 \u0938\u0947 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924\u00a0<\/span>N\u00a0\u092e\u0947\u0902 \u090f\u0915 \u0926\u094d\u0935\u093f\u0906\u0927\u093e\u0930\u0940 \u0938\u0902\u0915\u094d\u0930\u093f\u092f\u093e \u2018<\/span>o\u2019\u00a0\u092e\u0947\u0902 \u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0915\u094c\u0928 \u0938\u0924\u094d\u092f \u0939\u0948\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A)\u00a0\u0938\u0902\u0915\u094d\u0930\u093f\u092f\u093e \u0938\u093e\u0939\u0935\u0930\u094d\u0937 \u0914\u0930 \u0915\u092e \u0935\u093f\u0928\u093f\u092e\u092f \u0939\u0948<\/span><\/span><\/p>\n

(B)\u00a0\u0938\u0902\u0915\u094d\u0930\u093f\u092f\u093e \u0915\u094d\u0930\u092e \u0935\u093f\u0928\u093f\u092e\u092f \u0939\u0948 \u0915\u093f\u0928\u094d\u0924\u0941 \u0938\u093e\u0939\u091a\u0930\u094d\u092f \u0928\u0939\u0940\u0902 \u0939\u0948\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

(C)\u00a0\u0938\u0902\u0915\u094d\u0930\u093f\u092f\u093e \u0938\u093e\u0939\u091a\u0930\u094d\u092f \u0939\u0948 \u0915\u093f\u0928\u094d\u0924\u0941 \u0915\u094d\u0930\u092e \u0935\u093f\u0928\u093f\u092e\u092f \u0928\u0939\u0940\u0902 \u0939\u0948\u0964<\/span><\/span><\/p>\n

(D)\u00a0\u0907\u0928\u092e\u0947\u0902 \u0938\u0947 \u0915\u094b\u0908<\/span>\u00a0\u0928\u0939\u0940\u0902<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

41.\u00a0\u092f\u0926\u093f\u00a0<\/span>$\\displaystyle f:R\\to R$\u00a0\u0907\u0938 \u092a\u094d\u0930\u0915\u093e\u0930 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0939\u0948 \u0915\u093f\u00a0<\/span>$\\displaystyle f(x)={{(3-{{x}^{3}})}^{{\\frac{1}{3}}}}$\u00a0\u0924\u092c\u00a0<\/span>$\\displaystyle fof(x)$\u00a0\u0939\u0948<\/span><\/span><\/b><\/span><\/p>\n

(A) $\\displaystyle {{x}^{{\\frac{1}{3}}}}$<\/span><\/p>\n

(B) $\\displaystyle {{x}^{3}}$<\/span><\/p>\n

(C) $\\displaystyle (3-{{x}^{3}})$<\/span><\/p>\n

(D) $\\displaystyle x$\u00a0\u2713<\/span><\/b><\/span><\/p>\n

\u00a0<\/span><\/p>\n

42.\u00a0\u0935\u093e\u0938\u094d\u0924\u0935\u093f\u0915 \u0938\u0902\u0916\u094d\u092f\u093e\u0913\u0902 \u0915\u0947 \u0938\u092e\u0941\u091a\u094d\u091a\u092f \u092e\u0947\u0902 \u0938\u0902\u092c\u0902\u0927 \u091b\u094b\u091f\u093e \u0939\u0948\u2019 \u091c\u093f\u0938\u092e\u0947 \u0915\u0948\u0938\u093e \u0938\u0902\u092c\u0902\u0927<\/span><\/span><\/b><\/span><\/p>\n

(A)\u00a0\u0915\u0947\u0935\u0932 \u0938\u092e\u092e\u093f\u0924<\/span><\/span><\/p>\n

(B)\u00a0\u0915\u0947\u0935\u0932 \u0938\u0902\u0915\u094d\u0930\u093e\u092e\u0915\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

(C)\u00a0\u0915\u0947\u0935\u0932 \u0938\u094d\u0935<\/span><\/span><\/p>\n

(D)\u00a0\u0924\u0941\u0932\u094d\u092f\u0924\u093e \u0938\u0902\u092c\u0902\u0927<\/span><\/span><\/p>\n

\u00a0<\/span><\/p>\n

43.\u00a0\u0938\u0902\u092c\u0902\u0927\u00a0<\/span>R\u00a0\u091c\u0939\u093e\u0901\u00a0<\/span>R= {(2, 2).(3, 3), (2, 3) (3, 2), (3.1), ( 2, 1)},\u00a0\u0938\u092e\u0941\u091a\u094d\u091a\u092f\u00a0<\/span>A = {1, 2, 3}\u00a0\u092a\u0930 \u0915\u0948\u0938\u093e \u0938\u0902\u092c\u0902\u0927 \u0939\u0948<\/span>?<\/span><\/b><\/span><\/p>\n

(A)\u00a0\u0938\u094d\u0935\u0924\u0941\u0932\u094d\u092f<\/span><\/span><\/p>\n

(B)\u00a0\u0938\u092e\u092e\u093f\u0924<\/span><\/span><\/p>\n

(C)\u00a0\u0924\u0941\u0932\u094d\u092f\u0924\u093e \u0938\u0902\u092c\u0902\u0927<\/span><\/span><\/p>\n

(D)\u00a0\u0938\u0902\u0915\u094d\u0930\u093e\u092e\u0915\u00a0<\/span>\u2713<\/span><\/b><\/span><\/p>\n

\u00a0<\/span><\/p>\n

44.\u00a0\u092e\u093e\u0928 \u0932\u093f\u092f\u093e \u0915\u093f\u00a0<\/span>A = {1, 2, 3}\u00a0\u092a\u0930 \u090f\u0915 \u0938\u0902\u092c\u0902\u0927\u00a0<\/span>R= {(1,2), (2, 3) (1, 1)}\u00a0\u0926\u093f\u092f\u093e \u0917\u092f\u093e \u0939\u0948\u0964\u00a0<\/span>AxA\u00a0\u0915\u093e \u0915\u094c\u0928-\u0938\u093e \u0905\u0935\u092f\u0935\u00a0<\/span>R\u00a0\u092e\u0947\u0902 \u0936\u093e\u092e\u093f\u0932 \u0915\u093f\u092f\u093e \u091c\u093e\u090f \u0915\u093f \u092a\u0930\u093f\u0923\u093e\u092e\u0940 \u0938\u0902\u092c\u0902\u0927 \u0938\u0902\u0915\u094d\u0930\u092e\u093f\u0924 \u0939\u094b \u091c\u093e\u090f\u00a0<\/span>?<\/span><\/b><\/span><\/p>\n

(A) (3, 2)<\/span><\/p>\n

(B) (2, 1)<\/span><\/p>\n

(C) (2, 2)<\/span><\/p>\n

(D) (1, 3)\u00a0\u2713<\/span><\/b><\/span><\/p>\n

\u00a0<\/span><\/p>\n

45.\u00a0\u092e\u093e\u0928\u093e \u0915\u093f\u00a0<\/span>A = {1, 2, 3},\u00a0\u0924\u094b (<\/span>1, 2)\u00a0\u0924\u0925\u093e (<\/span>2, 1)\u00a0\u0915\u094b \u0936\u093e\u092e\u093f\u0932 \u0915\u0930\u0924\u0947 \u0939\u0941\u090f \u0915\u093f\u0924\u0928\u0947 \u0924\u0941\u0932\u094d\u092f\u0924\u093e \u0938\u0902\u092c\u0902\u0927\u00a0<\/span>A\u00a0\u092a\u0930 \u092a\u0930\u093f\u092d\u093e\u0937\u093f\u0924 \u0939\u094b \u0938\u0915\u0924\u093e \u0939\u0948<\/span>?<\/span><\/b><\/span><\/p>\n

(A) 3<\/span><\/p>\n

(B) 1<\/span><\/p>\n

(C) 2\u00a0\u2713<\/span><\/b><\/span><\/p>\n

(D) 4<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"

1.\u00a0\u0928\u093f\u092e\u094d\u0928\u0932\u093f\u0916\u093f\u0924 \u092e\u0947\u0902 \u0915\u093f\u0938\u0915\u093e \u092a\u094d\u0930\u0924\u093f\u0932\u094b\u092e \u092b\u0932\u0928 \u0939\u094b\u0924\u093e \u0939\u0948\u00a0? (A)\u00a0\u090f\u0915\u0948\u0915 \u0905\u0902\u0924\u0903 \u0915\u094d\u0937\u0947\u092a\u0940 (B)\u00a0\u090f\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915\u00a0\u2713 (C)\u00a0\u0905\u0928\u0947\u0915\u0948\u0915 \u0905\u0902\u0924\u0903 \u0915\u094d\u0937\u0947\u092a\u0940 (D)\u00a0\u0905\u0928\u0947\u0915\u0948\u0915 \u0906\u091a\u094d\u091b\u093e\u0926\u0915 \u00a0 2.\u00a0\u0938\u092e\u0941\u091a\u094d\u091a\u092f\u00a0A =<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[15],"tags":[],"class_list":["post-91","post","type-post","status-publish","format-standard","hentry","category-objective"],"_links":{"self":[{"href":"https:\/\/class12.studyguruji.in\/index.php?rest_route=\/wp\/v2\/posts\/91","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/class12.studyguruji.in\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/class12.studyguruji.in\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/class12.studyguruji.in\/index.php?rest_route=\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/class12.studyguruji.in\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=91"}],"version-history":[{"count":3,"href":"https:\/\/class12.studyguruji.in\/index.php?rest_route=\/wp\/v2\/posts\/91\/revisions"}],"predecessor-version":[{"id":1601,"href":"https:\/\/class12.studyguruji.in\/index.php?rest_route=\/wp\/v2\/posts\/91\/revisions\/1601"}],"wp:attachment":[{"href":"https:\/\/class12.studyguruji.in\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=91"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/class12.studyguruji.in\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=91"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/class12.studyguruji.in\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=91"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}